Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1
2:59
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Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1
Q) Show that the derivative of tan^(βˆ’1) (secπ‘₯+tanπ‘₯),[βˆ’πœ‹/2π‘₯πœ‹/2] with respect to x is equal to 1/2. #continuityanddifferentia CBSE Class 12 Maths PYQ 2026 | Continuity of Piecewise Function at x = 3 | Board Exam Question | Functions Chapter class 12th maths chapter number 5 Medium volume : class 12 maths chapter 5 exercise 5.1 ...
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#continuity
Q) Differential of 𝑒^(𝑒^π‘₯ ) with respect to x is #continuityanddifferentiabilityclass12 #cbse202
Q) Differential of 𝑒^(𝑒^π‘₯ ) with respect to x is #continuityanddifferentiabilityclass12 #cbse202
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Q) If y=tan^(βˆ’1) ((1βˆ’cosx)/sinx), then dy/dx is equal to #continuity_and_differentiability #maths
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Q) If tan^(βˆ’1) π‘₯=3𝑦, thenCBSE Class 12 Maths PYQ 2026 | Continuity of Piecewise Function at
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Q) Find the value of π‘˜, so that 𝑓(π‘₯)={(π‘˜cosπ‘₯/(πœ‹βˆ’2π‘₯), if π‘₯β‰ πœ‹/2@3, if π‘₯=πœ‹/2) is continu
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Q) Find the value of π‘˜, so that 𝑓(π‘₯)={(π‘˜cosπ‘₯/(πœ‹βˆ’2π‘₯), if π‘₯β‰ πœ‹/2@3, if π‘₯=πœ‹/2) is continu
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Differentiate (5^x/x^5 ) with respect to x #cbse2027 #maths #continuityanddifferentiabilityclass12
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Q) If y=π‘₯+tanπ‘₯, then prove that cos^2 π‘₯ ( d^2 𝑦)/( dπ‘₯^2 )βˆ’2𝑦+2π‘₯=0 #cbse2027 #maths #differen
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Q) If y=π‘₯+tanπ‘₯, then prove that cos^2 π‘₯ ( d^2 𝑦)/( dπ‘₯^2 )βˆ’2𝑦+2π‘₯=0 #cbse2027 #maths #differen
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If √π‘₯+βˆšπ‘¦=βˆšπ‘Ž, then 𝑑𝑦/𝑑π‘₯ is(A) (βˆ’βˆšπ‘₯)/√y(B) βˆ’1/2 βˆšπ‘¦/√π‘₯(C) βˆ’βˆšπ‘¦/√π‘₯(D) (βˆ’2βˆšπ‘¦)/√π‘₯ #maths
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Q) If 𝑓(π‘₯)={(sinπ‘₯/π‘₯+cosπ‘₯, π‘₯β‰ 0 π‘˜, π‘₯=0) is continuous at π‘₯=0, then the value of π‘˜ is :
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Find k so that 𝑓(π‘₯)={((π‘₯^2βˆ’2π‘₯βˆ’3)/(π‘₯+1), π‘₯β‰ βˆ’1 π‘˜, π‘₯=βˆ’1) is continuous at x=βˆ’1.#cbse2027 #maths
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Find the values of π›Œ if the function 𝐟(𝐱)={((〖𝐬𝐒𝐧^𝟐 π›Œπ±)/𝐱^𝟐 , 𝐒𝐟 π±β‰ πŸŽ 𝟏, 𝐒𝐟 𝐱=𝟎)
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If 𝑓(π‘₯)={ ((sin^2 π‘Žπ‘₯)/π‘₯^2 if π‘₯β‰ 0 1 , if π‘₯=0) is continuous at π‘₯=0, then the value of ' π‘Ž β€˜
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