A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Nov 25, 2013 · It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).

Jun 16, 2013 · -2 int() is the constructor of class int. It will initialise your variable a to the default value of an integer, i.e. 0. Even if you don't call the constructor explicitly, the default …

Dec 30, 2011 · int a = 5; int& b = a; b = 7; cout << a; prints out 7, and replacing int& b with int &b also prints out 7. In fact so does int&b and int & b. I tested this kind of behavior with a simple …

64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system. Of course, the well-known behavior comes in, when trying to define multiple …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

7 c is a double variable, but the value being assigned to it is an int value because it results from the division of two int s, which gives you "integer division" (dropping the remainder). So what …

Apr 21, 2011 · 29 int and unsigned int are two distinct integer types. (int can also be referred to as signed int, or just signed; unsigned int can also be referred to as unsigned.) As the names …

An int variable holds a 32 bit signed integer value. An Integer (with capital I) holds a reference to an object of (class) type Integer, or to null. Java automatically casts between the two; from …

Mar 14, 2012 · int is a primitive type allowed by the C# compiler, whereas Int32 is the Framework Class Library type (available across languages that abide by CLS). In fact, int translates to …