Explanation: #int (x^2+1)^2dx=# #int (x^4+2x^2+1)dx=# #x^5/5+2x^3/3+x+c# , #c# #in# #RR# Answer link You can reuse this answer

If you know the formula of f' (x), then you can find the formula f (x) except for its constant term by taking an antiderivative f (x)=\int f' (x)dx. If you have an additional information about f (x) such as a point on …

The antiderivative cannot be calculated using u-subs, trig-subs, integration by parts, or other similar methods of integration, so I used a series representation to integrate.

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int1/sqrt (x+1)dx=2sqrt (x+1)+c int1/sqrt (x+1)dx=2int ( (x+1)')/ (2sqrt (x+1))dx= 2int (sqrt (x+1))'dx=2sqrt (x+1)+c color (white) (aa) , cinRR

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